2(2x+3)=3(x-2)+10

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Solution for 2(2x+3)=3(x-2)+10 equation: 



2(2x+3)=3(x-2)+10

We move all terms to the left:

2(2x+3)-(3(x-2)+10)=0

We multiply parentheses

4x-(3(x-2)+10)+6=0



We calculate terms in parentheses: -(3(x-2)+10), so:

3(x-2)+10

We multiply parentheses

3x-6+10

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

4x-3x-4+6=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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