2(2x+4)+3(3x-2)=41

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Solution for 2(2x+4)+3(3x-2)=41 equation:



2(2x+4)+3(3x-2)=41
We move all terms to the left:
2(2x+4)+3(3x-2)-(41)=0
We multiply parentheses
4x+9x+8-6-41=0
We add all the numbers together, and all the variables
13x-39=0
We move all terms containing x to the left, all other terms to the right
13x=39
x=39/13
x=3

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