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2(2x+4)+5=3(x-5)
We move all terms to the left:
2(2x+4)+5-(3(x-5))=0
We multiply parentheses
4x-(3(x-5))+8+5=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
4x-(3x-15)+13=0
We get rid of parentheses
4x-3x+15+13=0
We add all the numbers together, and all the variables
x+28=0
We move all terms containing x to the left, all other terms to the right
x=-28
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