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2(2x+4)=(3x+x)+(10-2)
We move all terms to the left:
2(2x+4)-((3x+x)+(10-2))=0
We add all the numbers together, and all the variables
2(2x+4)-((+4x)+8)=0
We multiply parentheses
4x-((+4x)+8)+8=0
We calculate terms in parentheses: -((+4x)+8), so:We get rid of parentheses
(+4x)+8
We get rid of parentheses
4x+8
Back to the equation:
-(4x+8)
4x-4x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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