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2(2x+4)=-4(3x-5)+5x
We move all terms to the left:
2(2x+4)-(-4(3x-5)+5x)=0
We multiply parentheses
4x-(-4(3x-5)+5x)+8=0
We calculate terms in parentheses: -(-4(3x-5)+5x), so:We get rid of parentheses
-4(3x-5)+5x
We add all the numbers together, and all the variables
5x-4(3x-5)
We multiply parentheses
5x-12x+20
We add all the numbers together, and all the variables
-7x+20
Back to the equation:
-(-7x+20)
4x+7x-20+8=0
We add all the numbers together, and all the variables
11x-12=0
We move all terms containing x to the left, all other terms to the right
11x=12
x=12/11
x=1+1/11
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