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2(2x+4)=2(2x-4)
We move all terms to the left:
2(2x+4)-(2(2x-4))=0
We multiply parentheses
4x-(2(2x-4))+8=0
We calculate terms in parentheses: -(2(2x-4)), so:We get rid of parentheses
2(2x-4)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
4x-4x+8+8=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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