2(2x+4)=3/4(23-8x)

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Solution for 2(2x+4)=3/4(23-8x) equation: 



2(2x+4)=3/4(23-8x)

We move all terms to the left:

2(2x+4)-(3/4(23-8x))=0



Domain of the equation: 4(23-8x))!=0

x∈R



We add all the numbers together, and all the variables

2(2x+4)-(3/4(-8x+23))=0

We multiply parentheses

4x-(3/4(-8x+23))+8=0

We multiply all the terms by the denominator


4x*4(-8x+23))-(3+8*4(-8x+23))=0

Wy multiply elements

16x^2(-+32x(-=0

We use the square of the difference formula

16x^2(-32x(-=0

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