2(2x+4)=37-(4x+5)

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Solution for 2(2x+4)=37-(4x+5) equation: 



2(2x+4)=37-(4x+5)

We move all terms to the left:

2(2x+4)-(37-(4x+5))=0

We multiply parentheses

4x-(37-(4x+5))+8=0



We calculate terms in parentheses: -(37-(4x+5)), so:

37-(4x+5)

determiningTheFunctionDomain
-(4x+5)+37

We get rid of parentheses

-4x-5+37

We add all the numbers together, and all the variables

-4x+32

Back to the equation:

-(-4x+32)



We get rid of parentheses

4x+4x-32+8=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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