2(2x+4x-1)=68

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Solution for 2(2x+4x-1)=68 equation: 



2(2x+4x-1)=68

We move all terms to the left:

2(2x+4x-1)-(68)=0

We add all the numbers together, and all the variables

2(6x-1)-68=0

We multiply parentheses

12x-2-68=0

We add all the numbers together, and all the variables

12x-70=0

We move all terms containing x to the left, all other terms to the right

12x=70

x=70/12

x=5+5/6

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