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2(2x+5)+2(6x-1)=120
We move all terms to the left:
2(2x+5)+2(6x-1)-(120)=0
We multiply parentheses
4x+12x+10-2-120=0
We add all the numbers together, and all the variables
16x-112=0
We move all terms containing x to the left, all other terms to the right
16x=112
x=112/16
x=7
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