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2(2x+5)=3(x-4)
We move all terms to the left:
2(2x+5)-(3(x-4))=0
We multiply parentheses
4x-(3(x-4))+10=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
4x-3x+12+10=0
We add all the numbers together, and all the variables
x+22=0
We move all terms containing x to the left, all other terms to the right
x=-22
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