2(2x+9)=(3x+35)

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Solution for 2(2x+9)=(3x+35) equation: 



2(2x+9)=(3x+35)

We move all terms to the left:

2(2x+9)-((3x+35))=0

We multiply parentheses

4x-((3x+35))+18=0



We calculate terms in parentheses: -((3x+35)), so:

(3x+35)

We get rid of parentheses

3x+35

Back to the equation:

-(3x+35)



We get rid of parentheses

4x-3x-35+18=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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