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2(2x-1)(3x-1)=0
We multiply parentheses ..
2(+6x^2-2x-3x+1)=0
We multiply parentheses
12x^2-4x-6x+2=0
We add all the numbers together, and all the variables
12x^2-10x+2=0
a = 12; b = -10; c = +2;
Δ = b2-4ac
Δ = -102-4·12·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*12}=\frac{8}{24} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*12}=\frac{12}{24} =1/2 $
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