2(2x-1)+3=3(x-1)+8

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Solution for 2(2x-1)+3=3(x-1)+8 equation: 



2(2x-1)+3=3(x-1)+8

We move all terms to the left:

2(2x-1)+3-(3(x-1)+8)=0

We multiply parentheses

4x-(3(x-1)+8)-2+3=0



We calculate terms in parentheses: -(3(x-1)+8), so:

3(x-1)+8

We multiply parentheses

3x-3+8

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

4x-(3x+5)+1=0

We get rid of parentheses

4x-3x-5+1=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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