2(2x-1)+7=3(4x-2)-5

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Solution for 2(2x-1)+7=3(4x-2)-5 equation: 



2(2x-1)+7=3(4x-2)-5

We move all terms to the left:

2(2x-1)+7-(3(4x-2)-5)=0

We multiply parentheses

4x-(3(4x-2)-5)-2+7=0



We calculate terms in parentheses: -(3(4x-2)-5), so:

3(4x-2)-5

We multiply parentheses

12x-6-5

We add all the numbers together, and all the variables

12x-11

Back to the equation:

-(12x-11)



We add all the numbers together, and all the variables

4x-(12x-11)+5=0

We get rid of parentheses

4x-12x+11+5=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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