2(2x-1)+8=2(x+3)+2

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Solution for 2(2x-1)+8=2(x+3)+2 equation:



2(2x-1)+8=2(x+3)+2
We move all terms to the left:
2(2x-1)+8-(2(x+3)+2)=0
We multiply parentheses
4x-(2(x+3)+2)-2+8=0
We calculate terms in parentheses: -(2(x+3)+2), so:
2(x+3)+2
We multiply parentheses
2x+6+2
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
We add all the numbers together, and all the variables
4x-(2x+8)+6=0
We get rid of parentheses
4x-2x-8+6=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1

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