2(2x-1)+8=2(x+3)+2

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Solution for 2(2x-1)+8=2(x+3)+2 equation: 



2(2x-1)+8=2(x+3)+2

We move all terms to the left:

2(2x-1)+8-(2(x+3)+2)=0

We multiply parentheses

4x-(2(x+3)+2)-2+8=0



We calculate terms in parentheses: -(2(x+3)+2), so:

2(x+3)+2

We multiply parentheses

2x+6+2

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

4x-(2x+8)+6=0

We get rid of parentheses

4x-2x-8+6=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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