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2(2x-1)-7x=23-5(x+3)
We move all terms to the left:
2(2x-1)-7x-(23-5(x+3))=0
We add all the numbers together, and all the variables
-7x+2(2x-1)-(23-5(x+3))=0
We multiply parentheses
-7x+4x-(23-5(x+3))-2=0
We calculate terms in parentheses: -(23-5(x+3)), so:We add all the numbers together, and all the variables
23-5(x+3)
determiningTheFunctionDomain -5(x+3)+23
We multiply parentheses
-5x-15+23
We add all the numbers together, and all the variables
-5x+8
Back to the equation:
-(-5x+8)
-3x-(-5x+8)-2=0
We get rid of parentheses
-3x+5x-8-2=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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