2(2x-1)=(4x-1)(4x+1)

Solution for 2(2x-1)=(4x-1)(4x+1) equation:

2(2x-1)=(4x-1)(4x+1)

We move all terms to the left:

2(2x-1)-((4x-1)(4x+1))=0

We use the square of the difference formula

16x^2+2(2x-1)+1=0

We multiply parentheses

16x^2+4x-2+1=0

We add all the numbers together, and all the variables

16x^2+4x-1=0

a = 16; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·16·(-1)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{5}}{2*16}=\frac{-4-4\sqrt{5}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{5}}{2*16}=\frac{-4+4\sqrt{5}}{32}
$