2(2x-2)-2=2(x-5)+20

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Solution for 2(2x-2)-2=2(x-5)+20 equation: 



2(2x-2)-2=2(x-5)+20

We move all terms to the left:

2(2x-2)-2-(2(x-5)+20)=0

We multiply parentheses

4x-(2(x-5)+20)-4-2=0



We calculate terms in parentheses: -(2(x-5)+20), so:

2(x-5)+20

We multiply parentheses

2x-10+20

We add all the numbers together, and all the variables

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

4x-(2x+10)-6=0

We get rid of parentheses

4x-2x-10-6=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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