2(2x-2)=-2(x+3)+12

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Solution for 2(2x-2)=-2(x+3)+12 equation: 



2(2x-2)=-2(x+3)+12

We move all terms to the left:

2(2x-2)-(-2(x+3)+12)=0

We multiply parentheses

4x-(-2(x+3)+12)-4=0



We calculate terms in parentheses: -(-2(x+3)+12), so:

-2(x+3)+12

We multiply parentheses

-2x-6+12

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

4x+2x-6-4=0

We add all the numbers together, and all the variables

6x-10=0

We move all terms containing x to the left, all other terms to the right

6x=10

x=10/6

x=1+2/3

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