2(2x-2)=3(5-x)*

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Solution for 2(2x-2)=3(5-x)* equation: 



2(2x-2)=3(5-x)*

We move all terms to the left:

2(2x-2)-(3(5-x)*)=0

We add all the numbers together, and all the variables

2(2x-2)-(3(-1x+5)*)=0

We multiply parentheses

4x-(3(-1x+5)*)-4=0



We calculate terms in parentheses: -(3(-1x+5)*), so:

3(-1x+5)*

We multiply parentheses

-3x+15

Back to the equation:

-(-3x+15)



We get rid of parentheses

4x+3x-15-4=0

We add all the numbers together, and all the variables

7x-19=0

We move all terms containing x to the left, all other terms to the right

7x=19

x=19/7

x=2+5/7

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