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2(2x-3)+12=11+4x-5
We move all terms to the left:
2(2x-3)+12-(11+4x-5)=0
We add all the numbers together, and all the variables
2(2x-3)-(4x+6)+12=0
We multiply parentheses
4x-(4x+6)-6+12=0
We get rid of parentheses
4x-4x-6-6+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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