2(2x-3)+3x=2(x+1)+7

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Solution for 2(2x-3)+3x=2(x+1)+7 equation: 



2(2x-3)+3x=2(x+1)+7

We move all terms to the left:

2(2x-3)+3x-(2(x+1)+7)=0

We add all the numbers together, and all the variables

3x+2(2x-3)-(2(x+1)+7)=0

We multiply parentheses

3x+4x-(2(x+1)+7)-6=0



We calculate terms in parentheses: -(2(x+1)+7), so:

2(x+1)+7

We multiply parentheses

2x+2+7

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

7x-(2x+9)-6=0

We get rid of parentheses

7x-2x-9-6=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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