2(2x-3)+3x=7(x+1)

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Solution for 2(2x-3)+3x=7(x+1) equation: 



2(2x-3)+3x=7(x+1)

We move all terms to the left:

2(2x-3)+3x-(7(x+1))=0

We add all the numbers together, and all the variables

3x+2(2x-3)-(7(x+1))=0

We multiply parentheses

3x+4x-(7(x+1))-6=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We add all the numbers together, and all the variables

7x-(7x+7)-6=0

We get rid of parentheses

7x-7x-7-6=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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