2(2x-3)-(x+4)=3(x-2)+1

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Solution for 2(2x-3)-(x+4)=3(x-2)+1 equation:


Simplifying
2(2x + -3) + -1(x + 4) = 3(x + -2) + 1

Reorder the terms:
2(-3 + 2x) + -1(x + 4) = 3(x + -2) + 1
(-3 * 2 + 2x * 2) + -1(x + 4) = 3(x + -2) + 1
(-6 + 4x) + -1(x + 4) = 3(x + -2) + 1

Reorder the terms:
-6 + 4x + -1(4 + x) = 3(x + -2) + 1
-6 + 4x + (4 * -1 + x * -1) = 3(x + -2) + 1
-6 + 4x + (-4 + -1x) = 3(x + -2) + 1

Reorder the terms:
-6 + -4 + 4x + -1x = 3(x + -2) + 1

Combine like terms: -6 + -4 = -10
-10 + 4x + -1x = 3(x + -2) + 1

Combine like terms: 4x + -1x = 3x
-10 + 3x = 3(x + -2) + 1

Reorder the terms:
-10 + 3x = 3(-2 + x) + 1
-10 + 3x = (-2 * 3 + x * 3) + 1
-10 + 3x = (-6 + 3x) + 1

Reorder the terms:
-10 + 3x = -6 + 1 + 3x

Combine like terms: -6 + 1 = -5
-10 + 3x = -5 + 3x

Add '-3x' to each side of the equation.
-10 + 3x + -3x = -5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-10 + 0 = -5 + 3x + -3x
-10 = -5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-10 = -5 + 0
-10 = -5

Solving
-10 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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