2(2x-3)-(x-2)=3x-2(3x-4)

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Solution for 2(2x-3)-(x-2)=3x-2(3x-4) equation: 



2(2x-3)-(x-2)=3x-2(3x-4)

We move all terms to the left:

2(2x-3)-(x-2)-(3x-2(3x-4))=0

We multiply parentheses

4x-(x-2)-(3x-2(3x-4))-6=0

We get rid of parentheses

4x-x-(3x-2(3x-4))+2-6=0



We calculate terms in parentheses: -(3x-2(3x-4)), so:

3x-2(3x-4)

We multiply parentheses

3x-6x+8

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We add all the numbers together, and all the variables

3x-(-3x+8)-4=0

We get rid of parentheses

3x+3x-8-4=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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