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2(2x-3)-4=10x+6x-3
We move all terms to the left:
2(2x-3)-4-(10x+6x-3)=0
We add all the numbers together, and all the variables
2(2x-3)-(16x-3)-4=0
We multiply parentheses
4x-(16x-3)-6-4=0
We get rid of parentheses
4x-16x+3-6-4=0
We add all the numbers together, and all the variables
-12x-7=0
We move all terms containing x to the left, all other terms to the right
-12x=7
x=7/-12
x=-7/12
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