2(2x-3)=2(x+4)x

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Solution for 2(2x-3)=2(x+4)x equation: 



2(2x-3)=2(x+4)x

We move all terms to the left:

2(2x-3)-(2(x+4)x)=0

We multiply parentheses

4x-(2(x+4)x)-6=0



We calculate terms in parentheses: -(2(x+4)x), so:

2(x+4)x

We multiply parentheses

2x^2+8x

Back to the equation:

-(2x^2+8x)



We get rid of parentheses

-2x^2+4x-8x-6=0

We add all the numbers together, and all the variables

-2x^2-4x-6=0

a = -2; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·(-2)·(-6)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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