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2(2x-4)+2=4(x+2)-11
We move all terms to the left:
2(2x-4)+2-(4(x+2)-11)=0
We multiply parentheses
4x-(4(x+2)-11)-8+2=0
We calculate terms in parentheses: -(4(x+2)-11), so:We add all the numbers together, and all the variables
4(x+2)-11
We multiply parentheses
4x+8-11
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
4x-(4x-3)-6=0
We get rid of parentheses
4x-4x+3-6=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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