2(2x-4)+8=4x-2(-2+x)

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Solution for 2(2x-4)+8=4x-2(-2+x) equation: 



2(2x-4)+8=4x-2(-2+x)

We move all terms to the left:

2(2x-4)+8-(4x-2(-2+x))=0

We add all the numbers together, and all the variables

2(2x-4)-(4x-2(x-2))+8=0

We multiply parentheses

4x-(4x-2(x-2))-8+8=0



We calculate terms in parentheses: -(4x-2(x-2)), so:

4x-2(x-2)

We multiply parentheses

4x-2x+4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

4x-(2x+4)=0

We get rid of parentheses

4x-2x-4=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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