2(2x-4)-3=2(x-4)+9

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Solution for 2(2x-4)-3=2(x-4)+9 equation: 



2(2x-4)-3=2(x-4)+9

We move all terms to the left:

2(2x-4)-3-(2(x-4)+9)=0

We multiply parentheses

4x-(2(x-4)+9)-8-3=0



We calculate terms in parentheses: -(2(x-4)+9), so:

2(x-4)+9

We multiply parentheses

2x-8+9

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

4x-(2x+1)-11=0

We get rid of parentheses

4x-2x-1-11=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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