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2(2x-4)-4(5x+3)+(2x-4)(6x+2)=-3(2x+3)+(3x-8)(4x+2)
We move all terms to the left:
2(2x-4)-4(5x+3)+(2x-4)(6x+2)-(-3(2x+3)+(3x-8)(4x+2))=0
We multiply parentheses
4x-20x+(2x-4)(6x+2)-(-3(2x+3)+(3x-8)(4x+2))-8-12=0
We multiply parentheses ..
(+12x^2+4x-24x-8)+4x-20x-(-3(2x+3)+(3x-8)(4x+2))-8-12=0
We calculate terms in parentheses: -(-3(2x+3)+(3x-8)(4x+2)), so:We add all the numbers together, and all the variables
-3(2x+3)+(3x-8)(4x+2)
We multiply parentheses
-6x+(3x-8)(4x+2)-9
We multiply parentheses ..
(+12x^2+6x-32x-16)-6x-9
We get rid of parentheses
12x^2+6x-32x-6x-16-9
We add all the numbers together, and all the variables
12x^2-32x-25
Back to the equation:
-(12x^2-32x-25)
(+12x^2+4x-24x-8)-16x-(12x^2-32x-25)-20=0
We get rid of parentheses
12x^2-12x^2+4x-24x-16x+32x-8+25-20=0
We add all the numbers together, and all the variables
-4x-3=0
We move all terms containing x to the left, all other terms to the right
-4x=3
x=3/-4
x=-3/4
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