2(2x-5)+3(4x+6)=40

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Solution for 2(2x-5)+3(4x+6)=40 equation: 



2(2x-5)+3(4x+6)=40

We move all terms to the left:

2(2x-5)+3(4x+6)-(40)=0

We multiply parentheses

4x+12x-10+18-40=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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