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2(2x-6)=3(x-2)+x-6
We move all terms to the left:
2(2x-6)-(3(x-2)+x-6)=0
We multiply parentheses
4x-(3(x-2)+x-6)-12=0
We calculate terms in parentheses: -(3(x-2)+x-6), so:We get rid of parentheses
3(x-2)+x-6
We add all the numbers together, and all the variables
x+3(x-2)-6
We multiply parentheses
x+3x-6-6
We add all the numbers together, and all the variables
4x-12
Back to the equation:
-(4x-12)
4x-4x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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