2(2x-8)=4(1x-4)

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Solution for 2(2x-8)=4(1x-4) equation:


Simplifying
2(2x + -8) = 4(1x + -4)

Reorder the terms:
2(-8 + 2x) = 4(1x + -4)
(-8 * 2 + 2x * 2) = 4(1x + -4)
(-16 + 4x) = 4(1x + -4)

Reorder the terms:
-16 + 4x = 4(-4 + 1x)
-16 + 4x = (-4 * 4 + 1x * 4)
-16 + 4x = (-16 + 4x)

Add '16' to each side of the equation.
-16 + 16 + 4x = -16 + 16 + 4x

Combine like terms: -16 + 16 = 0
0 + 4x = -16 + 16 + 4x
4x = -16 + 16 + 4x

Combine like terms: -16 + 16 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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