2(2y+1)+3(y+4)=35

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Solution for 2(2y+1)+3(y+4)=35 equation: 


Simplifying
2(2y + 1) + 3(y + 4) = 35

Reorder the terms:
2(1 + 2y) + 3(y + 4) = 35
(1 * 2 + 2y * 2) + 3(y + 4) = 35
(2 + 4y) + 3(y + 4) = 35

Reorder the terms:
2 + 4y + 3(4 + y) = 35
2 + 4y + (4 * 3 + y * 3) = 35
2 + 4y + (12 + 3y) = 35

Reorder the terms:
2 + 12 + 4y + 3y = 35

Combine like terms: 2 + 12 = 14
14 + 4y + 3y = 35

Combine like terms: 4y + 3y = 7y
14 + 7y = 35

Solving
14 + 7y = 35

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 7y = 35 + -14

Combine like terms: 14 + -14 = 0
0 + 7y = 35 + -14
7y = 35 + -14

Combine like terms: 35 + -14 = 21
7y = 21

Divide each side by '7'.
y = 3

Simplifying
y = 3

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