2(2y+1)=(12-y)

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Solution for 2(2y+1)=(12-y) equation: 



2(2y+1)=(12-y)

We move all terms to the left:

2(2y+1)-((12-y))=0

We add all the numbers together, and all the variables

2(2y+1)-((-1y+12))=0

We multiply parentheses

4y-((-1y+12))+2=0



We calculate terms in parentheses: -((-1y+12)), so:

(-1y+12)

We get rid of parentheses

-1y+12

Back to the equation:

-(-1y+12)



We get rid of parentheses

4y+1y-12+2=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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