2(2y+15)=6(y+2)

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Solution for 2(2y+15)=6(y+2) equation:



2(2y+15)=6(y+2)
We move all terms to the left:
2(2y+15)-(6(y+2))=0
We multiply parentheses
4y-(6(y+2))+30=0
We calculate terms in parentheses: -(6(y+2)), so:
6(y+2)
We multiply parentheses
6y+12
Back to the equation:
-(6y+12)
We get rid of parentheses
4y-6y-12+30=0
We add all the numbers together, and all the variables
-2y+18=0
We move all terms containing y to the left, all other terms to the right
-2y=-18
y=-18/-2
y=+9

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