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2(2y+3)=4(y-1)
We move all terms to the left:
2(2y+3)-(4(y-1))=0
We multiply parentheses
4y-(4(y-1))+6=0
We calculate terms in parentheses: -(4(y-1)), so:We get rid of parentheses
4(y-1)
We multiply parentheses
4y-4
Back to the equation:
-(4y-4)
4y-4y+4+6=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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