2(2y+3)=4(y-1)

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Solution for 2(2y+3)=4(y-1) equation: 



2(2y+3)=4(y-1)

We move all terms to the left:

2(2y+3)-(4(y-1))=0

We multiply parentheses

4y-(4(y-1))+6=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

4y-4y+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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