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2(2y+3)=4-(y-12)
We move all terms to the left:
2(2y+3)-(4-(y-12))=0
We multiply parentheses
4y-(4-(y-12))+6=0
We calculate terms in parentheses: -(4-(y-12)), so:We get rid of parentheses
4-(y-12)
determiningTheFunctionDomain -(y-12)+4
We get rid of parentheses
-y+12+4
We add all the numbers together, and all the variables
-1y+16
Back to the equation:
-(-1y+16)
4y+1y-16+6=0
We add all the numbers together, and all the variables
5y-10=0
We move all terms containing y to the left, all other terms to the right
5y=10
y=10/5
y=2
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