2(2y+5)+7=-3(y-1)

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Solution for 2(2y+5)+7=-3(y-1) equation:



2(2y+5)+7=-3(y-1)
We move all terms to the left:
2(2y+5)+7-(-3(y-1))=0
We multiply parentheses
4y-(-3(y-1))+10+7=0
We calculate terms in parentheses: -(-3(y-1)), so:
-3(y-1)
We multiply parentheses
-3y+3
Back to the equation:
-(-3y+3)
We add all the numbers together, and all the variables
4y-(-3y+3)+17=0
We get rid of parentheses
4y+3y-3+17=0
We add all the numbers together, and all the variables
7y+14=0
We move all terms containing y to the left, all other terms to the right
7y=-14
y=-14/7
y=-2

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