2(2y-1)+3(1-y)=4(y+1)-9

Solution for 2(2y-1)+3(1-y)=4(y+1)-9 equation:

2(2y-1)+3(1-y)=4(y+1)-9

We move all terms to the left:

2(2y-1)+3(1-y)-(4(y+1)-9)=0

We add all the numbers together, and all the variables

2(2y-1)+3(-1y+1)-(4(y+1)-9)=0

We multiply parentheses

4y-3y-(4(y+1)-9)-2+3=0


We calculate terms in parentheses: -(4(y+1)-9), so:

4(y+1)-9

We multiply parentheses

4y+4-9

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)


We add all the numbers together, and all the variables

y-(4y-5)+1=0

We get rid of parentheses

y-4y+5+1=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2