2(2y-1)=3(4y+2)

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Solution for 2(2y-1)=3(4y+2) equation: 



2(2y-1)=3(4y+2)

We move all terms to the left:

2(2y-1)-(3(4y+2))=0

We multiply parentheses

4y-(3(4y+2))-2=0



We calculate terms in parentheses: -(3(4y+2)), so:

3(4y+2)

We multiply parentheses

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

4y-12y-6-2=0

We add all the numbers together, and all the variables

-8y-8=0

We move all terms containing y to the left, all other terms to the right

-8y=8

y=8/-8

y=-1

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