2(2y-2)+5y=4(3y-4)

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Solution for 2(2y-2)+5y=4(3y-4) equation: 



2(2y-2)+5y=4(3y-4)

We move all terms to the left:

2(2y-2)+5y-(4(3y-4))=0

We add all the numbers together, and all the variables

5y+2(2y-2)-(4(3y-4))=0

We multiply parentheses

5y+4y-(4(3y-4))-4=0



We calculate terms in parentheses: -(4(3y-4)), so:

4(3y-4)

We multiply parentheses

12y-16

Back to the equation:

-(12y-16)



We add all the numbers together, and all the variables

9y-(12y-16)-4=0

We get rid of parentheses

9y-12y+16-4=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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