2(2y-2)=3(y+5)

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Solution for 2(2y-2)=3(y+5) equation: 



2(2y-2)=3(y+5)

We move all terms to the left:

2(2y-2)-(3(y+5))=0

We multiply parentheses

4y-(3(y+5))-4=0



We calculate terms in parentheses: -(3(y+5)), so:

3(y+5)

We multiply parentheses

3y+15

Back to the equation:

-(3y+15)



We get rid of parentheses

4y-3y-15-4=0

We add all the numbers together, and all the variables

y-19=0

We move all terms containing y to the left, all other terms to the right

y=19

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