2(2y-2.3)=4(3y+2.2)

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Solution for 2(2y-2.3)=4(3y+2.2) equation: 



2(2y-2.3)=4(3y+2.2)

We move all terms to the left:

2(2y-2.3)-(4(3y+2.2))=0

We multiply parentheses

4y-(4(3y+2.2))-4.6=0



We calculate terms in parentheses: -(4(3y+2.2)), so:

4(3y+2.2)

We multiply parentheses

12y+8.8

Back to the equation:

-(12y+8.8)



We get rid of parentheses

4y-12y-8.8-4.6=0

We add all the numbers together, and all the variables

-8y-13.4=0

We move all terms containing y to the left, all other terms to the right

-8y=13.4

y=13.4/-8

y=-1+3.85714285714/5.71428571429

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