2(2y-3)=3(y+4)-18

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Solution for 2(2y-3)=3(y+4)-18 equation: 



2(2y-3)=3(y+4)-18

We move all terms to the left:

2(2y-3)-(3(y+4)-18)=0

We multiply parentheses

4y-(3(y+4)-18)-6=0



We calculate terms in parentheses: -(3(y+4)-18), so:

3(y+4)-18

We multiply parentheses

3y+12-18

We add all the numbers together, and all the variables

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

4y-3y+6-6=0

We add all the numbers together, and all the variables

y=0

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