2(2y-3)=6+y

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Solution for 2(2y-3)=6+y equation: 



2(2y-3)=6+y

We move all terms to the left:

2(2y-3)-(6+y)=0

We add all the numbers together, and all the variables

2(2y-3)-(y+6)=0

We multiply parentheses

4y-(y+6)-6=0

We get rid of parentheses

4y-y-6-6=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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