2(2y-3)=6y+12

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Solution for 2(2y-3)=6y+12 equation: 



2(2y-3)=6y+12

We move all terms to the left:

2(2y-3)-(6y+12)=0

We multiply parentheses

4y-(6y+12)-6=0

We get rid of parentheses

4y-6y-12-6=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9

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