2(2y-4)+3y=7

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Solution for 2(2y-4)+3y=7 equation: 



2(2y-4)+3y=7

We move all terms to the left:

2(2y-4)+3y-(7)=0

We add all the numbers together, and all the variables

3y+2(2y-4)-7=0

We multiply parentheses

3y+4y-8-7=0

We add all the numbers together, and all the variables

7y-15=0

We move all terms containing y to the left, all other terms to the right

7y=15

y=15/7

y=2+1/7

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